1 2 public static String slurp (InputStream in) throws IOException { 3 StringBuffer out = new StringBuffer(); 4 byte[] b = new byte[4096]; 5 for (int n; (n = in.read(b)) != -1;) { 6 out.append(new String(b, 0, n)); 7 } 8 return out.toString(); 9 }
Talchas posts on Feb 22, 2006 at 19:28
Of course, in 1.5 you would want to use StringBuilder.
philemine posts on Aug 08, 2006 at 11:40
Other way to do this:
public static String inputStreamAsString(InputStream stream)
throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(stream));
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
return sb.toString();
}
public static String inputStreamAsString(InputStream stream)
throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(stream));
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
return sb.toString();
}
The_Farwall posts on Sep 27, 2006 at 13:07
What's the significance of setting the byte array size to 4096, how was that determined/decided on?
Perlyking posts on Oct 26, 2006 at 12:21
One possible problem with the StringBuilder code above is that a "\n" is automatically appended to the end of the string, even if the original file on disk did not end with a newline. Your string may thus not be an accurate representation of the file.
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