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simple xmlrpc with python (See related posts)

code for the client :
   1  
   2  from xmlrpclib import ServerProxy
   3  
   4  print ServerProxy("http://127.0.0.1:9955").get_file()


code for the server :
   1  
   2  import SimpleXMLRPCServer
   3  
   4  def get_file():
   5      return "content"
   6  
   7  server = SimpleXMLRPCServer.SimpleXMLRPCServer(("127.0.0.1", 9955))
   8  server.register_function(get_file)
   9  server.serve_forever()

to python xmlrpc by manatlan on Wed Sep 07 16:48:09 -0400 2005

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