count lines, sentences, and words of a text file

mattisbusy (Matt Kaufman) — Sun, 24 Jul 2005 11:45:17 GMT



# count lines, sentences, and words of a text file





# set all the counters to zero



lines, blanklines, sentences, words = 0, 0, 0, 0



print '-' * 50



try:

  # use a text file you have, or google for this one ...



  filename = 'GettysburgAddress.txt'

  textf = open(filename, 'r')

except IOError:

  print 'Cannot open file %s for reading' % filename

  import sys

  sys.exit(0)



# reads one line at a time



for line in textf:

  print line,   # test



  lines += 1

  

  if line.startswith('\n'):

    blanklines += 1

  else:

    # assume that each sentence ends with . or ! or ?



    # so simply count these characters



    sentences += line.count('.') + line.count('!') + line.count('?')

    

    # create a list of words



    # use None to split at any whitespace regardless of length



    # so for instance double space counts as one space



    tempwords = line.split(None)

    print tempwords  # test



    

    # word total count



    words += len(tempwords)



    

textf.close()



print '-' * 50

print "Lines      : ", lines

print "Blank lines: ", blanklines

print "Sentences  : ", sentences

print "Words      : ", words



# optional console wait for keypress



from msvcrt import getch

getch()

DZone Snippets: open code

count lines, sentences, and words of a text file