http://snippets.dzone.com/posts Thu, 21 Aug 2008 01:49:25 GMT DZone Snippets: xpath code http://snippets.dzone.com/posts/show/4349 Given a node this will return an array containing the XPath <br />Usage: <br /> <br />getXPath(document.getElementById('myelement')); <br /> <br /><code> <br /> function getXPath(node, path) { <br /> path = path || []; <br /> if(node.parentNode) { <br /> path = getXPath(node.parentNode, path); <br /> } <br /> <br /> if(node.previousSibling) { <br /> var count = 1; <br /> var sibling = node.previousSibling <br /> do { <br /> if(sibling.nodeType == 1 && sibling.nodeName == node.nodeName) {count++;} <br /> sibling = sibling.previousSibling; <br /> } while(sibling); <br /> if(count == 1) {count = null;} <br /> } else if(node.nextSibling) { <br /> var sibling = node.nextSibling; <br /> do { <br /> if(sibling.nodeType == 1 && sibling.nodeName == node.nodeName) { <br /> var count = 1; <br /> sibling = null; <br /> } else { <br /> var count = null; <br /> sibling = sibling.previousSibling; <br /> } <br /> } while(sibling); <br /> } <br /> <br /> if(node.nodeType == 1) { <br /> path.push(node.nodeName.toLowerCase() + (node.id ? "[@id='"+node.id+"']" : count > 0 ? "["+count+"]" : '')); <br /> } <br /> return path; <br /> }; <br /> <br /></code> Mon, 23 Jul 2007 20:57:04 GMT http://snippets.dzone.com/posts/show/4349 sprsquish (Jeff Smick)