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DOM Parser Demo Code

//above class will search a movie/actor/producer name & will accordingly print other
//details
import javax.swing.text.html.parser.DocumentParser;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import java.util.*;
public class Movie_XML implements Movie
{

ArrayList<MovieDB> movies = new ArrayList<MovieDB>();

public ArrayList<MovieDB> searchByActorName(String nm,String key)
{
try
{
DocumentBuilderFactory docFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docFactory.newDocumentBuilder();
Document doc = docBuilder.parse("movie.xml");
NodeList nodeList = null;

if(key.equalsIgnoreCase("actor"))
nodeList = doc.getElementsByTagName("actor");
else if(key.equalsIgnoreCase("movie"))
nodeList = doc.getElementsByTagName("name");
else
nodeList = doc.getElementsByTagName("producer");

Node temp = null, parent=null;
NodeList childs = null;
for(int i=0;i<nodeList.getLength();i++)
{
temp = nodeList.item(i);
if(temp.getTextContent().equalsIgnoreCase(nm))
{
parent = temp.getParentNode();
childs = parent.getChildNodes();
MovieDB mDB = new MovieDB();
for(int j=0;j<childs.getLength();j++)
{
Node nd = childs.item(j);
if(nd.getNodeType() == Node.ELEMENT_NODE)
{
String name = nd.getNodeName();
//System.out.println(name);
if(name.equalsIgnoreCase("id"))
{
mDB.setId(nd.getTextContent());
}
if(name.equalsIgnoreCase("name"))
{
mDB.setName(nd.getTextContent());
}
if(name.equalsIgnoreCase("producer"))
{
mDB.setProducer(nd.getTextContent());
}
if(name.equalsIgnoreCase("director"))
{
mDB.setDirector(nd.getTextContent());
}
if(name.equalsIgnoreCase("music_director"))
{
mDB.setMusic_director(nd.getTextContent());
}
if(name.equalsIgnoreCase("actor"))
{
mDB.setActor(nd.getTextContent());
}
if(name.equalsIgnoreCase("actress"))
{
mDB.setActress(nd.getTextContent());
}
}
}
movies.add(mDB);
}
}
return movies;
}
catch(Exception e)
{
throw new CustomException("err in Searching by actor name",e);
}
}
}

//this class will call the above class by sending appropriate parmeters

import java.util.*;
import java.io.*;
public class XMLDemo
{
public static void main(String[] args)
{
try
{
InputStreamReader ir = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(ir);
while(true)
{
System.out.println("\n Enter the Choice : ");
System.out.println(" 1 : Search By Actor Name : ");
System.out.println(" 2 : Search By Movie Name : ");
System.out.println(" 3 : Search By Producer Name : ");
System.out.println(" 4 : Quit : ");
try
{
int ch = Integer.parseInt(br.readLine());
switch(ch)
{
case 1 :
System.out.println("Enter Actor Name : ");
String actorName = br.readLine();
search(actorName,"actor");
break;
case 2 :
System.out.println("Enter Movie Name");
String movieName = br.readLine();
search(movieName,"movie");
break;
case 3 :
System.out.println("Enter Producer Name");
String producerName = br.readLine();
search(producerName,"producer");
break;
case 4 :
System.out.println("Exiting");
System.exit(0);
default :
System.out.println("Invalid Choice !");
}
}
catch(Exception e)
{
System.out.println("Invalid Choice !");
}
}//end of while
}
catch(Exception e)
{
//e.printStackTrace();
throw new CustomException("err in main",e);
}
}

static void search(String name,String key)
{
try
{
ArrayList<MovieDB> movies = new ArrayList<MovieDB>();
Movie_XML obj = new Movie_XML();
movies = obj.searchByActorName(name,key);
int i =0;
System.out.println();
for(i=0;i<movies.size();i++)
{
MovieDB mDB = movies.get(i);
System.out.println("ID : "+mDB.getId());
System.out.println("Name : "+mDB.getName());
System.out.println("Producer : "+mDB.getProducer());
System.out.println("Director : "+mDB.getDirector());
System.out.println("Music : "+mDB.getMusic_director());
System.out.println("Actor : "+mDB.getActor());
System.out.println("Actress : "+mDB.getActress());
}
System.out.println(i+" Record Found!");
}
catch(Exception e)
{
throw new CustomException("err in byActor",e);
}
}
}

//this class will hold the details of the movie(id,name,---)

import java.util.*;
public class MovieDB
{
private String id,name,year;
private ArrayList<String> actor,actress;
private String director,producer,music_director;

public MovieDB()
{
actor = new ArrayList<String>();
actress = new ArrayList<String>();
}

public void setId(String id)
{
this.id = id;
}

public void setName(String name)
{
this.name = name;
}

public void setYear(String year)
{
this.year = year;
}

public void setDirector(String director)
{
this.director = director;
}

public void setProducer(String producer)
{
this.producer = producer;
}

public void setMusic_director(String music_director)
{
this.music_director = music_director;
}

public void setActor(String actor)
{
this.actor.add(actor);
}

public void setActress(String actress)
{
this.actress.add(actress);
}

public String getId()
{
return id;
}

public String getName()
{
return name;
}

public String getProducer()
{
return producer;
}

public String getDirector()
{
return director;
}

public String getMusic_director()
{
return music_director;
}

public ArrayList<String> getActor()
{
return actor;
}

public ArrayList<String> getActress()
{
return actress;
}
}

//movie interface

import java.util.*;
public interface Movie
{
public ArrayList<MovieDB> searchByActorName(String nm,String key);
}

to is example of the an one Above by sumit.tambekar on Apr 15, 2008

DOM Parser Demo Code

to is example of the an one Above by sumit.tambekar on Apr 15, 2008

dbg - debuging routine

A handy little routine to debug autoit scripts

dbg("Log this message")
Func dbg($msg, $error=@error, $extended=@extended, $ScriptLineNumber=@ScriptLineNumber)
    Local $out = "(" & $ScriptLineNumber & ")(" & $error & ")(" & $extended & ") := " & $msg 
    ;Output to application attaching a console to the script engine
    ConsoleWrite($msg & @CRLF)
    ;Output to debugger (dbgview.exe)
    DllCall("kernel32.dll", "none", "OutputDebugString", "str", $out)
EndFunc

to debug example AutoIt by uten on Oct 20, 2007

Generate combinations

Code generates all the combinations of n elements choosing k elements.

See this for definition.

See this for explanation.

#include <stdio.h>

/* Prints out a combination like {1, 2} */
void printc(int comb[], int k) {
	printf("{");
	int i;
	for (i = 0; i < k; ++i)
		printf("%d, ", comb[i] + 1);
	printf("\b\b}\n");
}

/*
	next_comb(int comb[], int k, int n)
		Generates the next combination of n elements as k after comb

	comb => the previous combination ( use (0, 1, 2, ..., k) for first)
	k => the size of the subsets to generate
	n => the size of the original set

	Returns: 1 if a valid combination was found
		0, otherwise
*/
int next_comb(int comb[], int k, int n) {
	int i = k - 1;
	++comb[i];
	while ((i >= 0) && (comb[i] >= n - k + 1 + i)) {
		--i;
		++comb[i];
	}

	if (comb[0] > n - k) /* Combination (n-k, n-k+1, ..., n) reached */
		return 0; /* No more combinations can be generated */

	/* comb now looks like (..., x, n, n, n, ..., n).
	Turn it into (..., x, x + 1, x + 2, ...) */
	for (i = i + 1; i < k; ++i)
		comb[i] = comb[i - 1] + 1;

	return 1;
}

int main(int argc, char *argv[]) {
	int n = 5; /* The size of the set; for {1, 2, 3, 4} it's 4 */
	int k = 3; /* The size of the subsets; for {1, 2}, {1, 3}, ... it's 2 */
	int comb[16]; /* comb[i] is the index of the i-th element in the
			combination */

	/* Setup comb for the initial combination */
	int i;
	for (i = 0; i < k; ++i)
		comb[i] = i;

	/* Print the first combination */
	printc(comb, k);

	/* Generate and print all the other combinations */
	while (next_comb(comb, k, n))
		printc(comb, k);

	return 0;
}

to c generate example algorithm combinations combinatorics by scvalex on Oct 17, 2007

Permutations

Generates all permutation of n. Uses the naive (stupid) "let's generate all imaginable possibilities and see which are permutations" algorithm.

Time: O(n!)

#include <stdio.h>

int next(int v[], int n) {
	int i = n - 1;
	v[i] = v[i] + 1;
	while ((i >= 0) && (v[i] > n)) {
		v[i] = 1;
		i--;
		if(i >= 0)
			v[i]++;
	}

	if (i < 0)
		return 0;
	return 1;
}

void printv(int v[],int n) {
	int i;

	for (i = 0; i < n; i++)
		printf("%d", v[i]);
	printf("\n");
}

int is_perm(int v[], int n) {
	int i, j;

	for (i = 0; i < n; i++)
		for (j = i + 1; j < n; j++)
			if (v[i] == v[j])
				return 0;

	return 1;
}

int main(int argc, char *argv[]) {
	int v[128];
	int n = 6;
	int i;
	for(i = 0; i <= n; i++)
		v[i] = i + 1;

	while (next(v,n))
		if (is_perm(v,n))
			printv(v,n);

	return 0;
}

to c permutation example stupid naive by scvalex on Oct 03, 2007

The Qeens Problem

Prints all valid ways to arrange n qeens on a n x n chessboard so that the qeens don't attack each other.

#include <iostream>
#include <vector>

typedef std::vector< int > Vect;
typedef std::vector< Vect > List;

const int n = 12;

bool checkRow(const Vect &v, int k) {
	for (int i = k - 1; i >= 0; --i)
		if (v[k] == v[i])
			return false;

	return true;
}

bool checkDiag(const Vect &v, int k) {
	for (int i = k - 1; i >= 0; --i)
		if (k - i == abs(v[k] - v[i]))
			return false;
	
	return true;
}

List filter(List l, int k) {
	List r;
	for (List::const_iterator it = l.begin(); it != l.end(); ++it) {
		if (checkRow(*it, k) && checkDiag(*it, k))
			r.push_back(*it);
	}
	
	return r;
}

List qeens(int k) {
	if (0 == k) {
		List l;
		l.push_back(Vect());
		return l;
	}
	
	List l = qeens(k - 1);
	List r;
	for (List::iterator it = l.begin(); it != l.end(); ++it) {
		for (int newRow = 1; newRow <= n; ++newRow) {
			Vect v(*it);
			v.push_back(newRow);
			r.push_back(v);
		}
	}
	
	r = filter(r, k - 1);
	
	return r;
}

void printS(List l) {
	for (List::const_iterator it = l.begin(); it != l.end(); ++it) {
		for (Vect::const_iterator jt = it->begin(); jt != it->end(); ++jt)
			std::cout << *jt << " ";
		std::cout << std::endl;
	}
}

int main(int argc, char *argv[]) {
	List l = qeens(n);
	
	printS(l);
	
	return 0;
}

to c++ STL example problem by scvalex on Oct 02, 2007

Quicksort

Qucksort written in C. Uses the Hoare partition algorithm.

typedef struct {
	int len;
	int elem[50240];
} vector;

void printv(char *str, vector v) {
	printf("%s", str);
	int i = 0;
	for (; i < v.len; ++i)
		printf("%d ", v.elem[i]);
	printf("\n");
}

#define MAX(a, b) ((a > b) ? (a) : (b))
#define MIN(a, b) ((a < b) ? (a) : (b))

int partition(vector *v, int p, int r) {
	int x;
	if (p + 3 < r)
		x = MIN(v->elem[p], MAX(v->elem[p+1], v->elem[p+2]));
	else
		x = v->elem[p];
	
	int i = p - 1;
	int j = r + 1;
	while (1) {
		do {
			--j;
		} while (v->elem[j] > x);
		do {
			++i;
		} while (v->elem[i] < x);

		if (i < j) {
			int aux = v->elem[j];
			v->elem[j] = v->elem[i];
			v->elem[i] = aux;
		} else
			return j;			
	}
}

void quicksort_real(vector *v, int p, int r) {
	if (p < r) {
		int q = partition(v, p, r);
		quicksort_real(v, p, q);
		quicksort_real(v, q + 1, r);
	}
}

void quicksort(vector *v) {
	printf("Quicksort...\n");
	quicksort_real(v, 0, v->len - 1);
}

to c example algorithm quicksort toocomplicated by scvalex on Oct 01, 2007

Strange square

For n = 8, builds
1 1 1 1 1 1 1 0
1 1 1 1 1 1 0 0
1 1 1 1 1 0 1 0
1 1 1 1 0 0 0 0
1 1 1 0 1 1 1 0
1 1 0 0 1 1 0 0
1 0 1 0 1 0 1 0
0 0 0 0 0 0 0 0

The algorithm, for a n x n matrix is:
1. Split the matrix into 4 matrices of the same size
2. Complete the top-left one with 1
3. Repeat for each of the other 3 matrices.

#include <stdio.h>
#include <stdlib.h>

int n;
int **T;

void printM() {
	int i,
		j;
	printf("\n");
	for (i = 0; i < n; ++i) {
		for (j = 0; j < n; ++j)
			printf("%d ", T[i][j]);
		printf("\n");
	}
}

void fill(int x1, int y1, int x2, int y2) {
	printf("%d %d %d %d\n", x1, y1, x2, y2);
	//getchar();
	
	if (x1 == x2) {
		//T[x1][y1] = 1;
		return;
	}
	
	int i,
		j;
	int xm = (x1 + x2) / 2;
	int ym = (y1 + y2) / 2;
	for (i = y1; i <= ym; ++i)
		for (j = x1; j <= xm; ++j)
			T[i][j] = 1;
	
	fill(x1, ym + 1, xm, y2);
	fill(xm + 1, y1, x2, ym);
	fill(xm + 1, ym + 1, x2, y2);
}

int main(int argc, char *argv[]) {
	n = 8;
	T = (int**)malloc(n * sizeof(int*));
	int i;
	for (i = 0; i < n; ++i)
		T[i] = (int*)malloc(n * sizeof(int));
	
	int j;
	for (i = 0; i < n; ++i)
		for (j = 0; j < n; ++j)
			T[i][j] = 0;
	
	fill(0, 0, n - 1, n - 1);
	printM();
	
	return 0;
}

to c example matrix problem divide-et-impera by scvalex on Oct 01, 2007

C - Simple Example GTK

// gcc file.c -o file.o `pkg-config --libs --cflags gtk+-2.0`

#include <gtk/gtk.h>
#include <stdlib.h>

void displayUI()
{
	GtkWidget* mainWindow = gtk_window_new(GTK_WINDOW_TOPLEVEL);

	gtk_window_set_default_size(GTK_WINDOW(mainWindow), 400, 300);
	gtk_window_set_title(GTK_WINDOW(mainWindow), "GTK Simple Example");
	gtk_window_set_position(GTK_WINDOW(mainWindow), GTK_WIN_POS_CENTER_ALWAYS);

	gtk_signal_connect(GTK_OBJECT(mainWindow), "destroy", G_CALLBACK(gtk_main_quit), NULL);

	gtk_widget_show_all(mainWindow);
}

int main(int argc, char *argv[])
{
	gtk_init(&argc, &argv);

	displayUI();

	gtk_main();

	return EXIT_SUCCESS;
}

to c gtk connect window example by whitetiger on Dec 05, 2006

Ruby - Sostituire elementi

// Sostituisce "old" con "new" in tutti i file

ruby .i.bak -pe 'sub "old", "new"' *

to ruby text substitute example by whitetiger on Nov 24, 2006

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DOM Parser Demo Code

DOM Parser Demo Code

dbg - debuging routine

Generate combinations

Permutations

The Qeens Problem

Quicksort

Strange square

C - Simple Example GTK

Ruby - Sostituire elementi